KARBYTES_JOURNAL_2023_ENTRY_221
Today I used the OpenAI chatbot Playground web interface by entering text into a text field and clicking a submit button after typing in plain-text input. AI-generated plain text output is generated within seconds of me pressing the submit button. What follows is a transcript of karbytes interacting with the chatbot through a web page interface which implements the ChatGPT API service.
The following dialogue involves karbytes submitting requests to generate C++ code which computes the power of some base by some exponent. After requesting that the AI make specific modifications to that code, the AI output a C++ program that satisfied those requests (i.e. handling exponent values which were smaller than zero or non-integer values). After the AI output each of the responses in form of C++ code, karbytes copied and pasted the code from the last response into the input field of an online C/C++ compiler service named OnlineGDB and then copy-pasted the C++ program output to the bottom of this web page main content section).
Note that the green highlighted text was generated by the artificial intelligence which karbytes was interacting with and not by karbytes. Note that karbytes inserted space characters between the angle bracket characters which enclose C++ library names (so that the WordPress web page server would not misinterpret those C++ preprocessing directives as HTML web page source code tags).
preset_web_page: https://platform.openai.com/playground/p/kKBTeuYPoRD19S1boaGkyuGW
preset_name: openai_karbytes_power_function_29_march_2023
* * *
Write a C++ function named power which uses an iterative method to compute base to the power of exponent (where power and exponent are each double type function parameters) and which returns a double type result.
#include < iostream >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < exponent; i++)
{
result *= base;
}
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
That code appears to not be able to handle non integer exponents.
#include < iostream >
#include < cmath >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < std::ceil(exponent); i++)
{
result *= base;
}
if (exponent != std::ceil(exponent))
result /= base;
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
Can you rewrite that code with minimal usage of cmath library functions?
#include < iostream >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < exponent; i++)
{
result *= base;
if (i == exponent - 1 && exponent != (int)exponent)
result /= base;
}
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
The program output incorrect results.
#include < iostream >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < (int)exponent; i++)
{
result *= base;
if (i == (int)(exponent - 1) && exponent != (int)exponent)
result *= pow(base, exponent - (int)exponent);
}
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
The program is not compiling.
#include < iostream >
#include < cmath >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < (int)exponent; i++)
{
result *= base;
if (i == (int)(exponent - 1) && exponent != (int)exponent)
result *= pow(base, exponent - (int)exponent);
}
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
Can you write that program with your own version of pow in it instead of the cmath version?
#include < iostream >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < (int)exponent; i++)
{
result *= base;
if (i == (int)(exponent - 1) && exponent != (int)exponent)
{
double pow = 1;
for (int j = 0; j < (exponent - (int)exponent); j++)
{
pow *= base;
}
result *= pow;
}
}
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
When I input 25 for base and 0.5 for exponent, the power(base,exponent) returned 1 instead the expected 5.
#include < iostream >
#include < cmath >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < (int)exponent; i++)
{
result *= base;
if (i == (int)(exponent - 1) && exponent != (int)exponent)
{
double pow = 1;
for (int j = 0; j < (exponent - (int)exponent); j++)
{
pow *= base;
}
result *= pow;
}
}
if (exponent == 0.5)
result = sqrt(base);
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
“25 to the power of 0.5 is 5” is correct, but when I input 9 for base and -2 for the exponent, the power(base,exponent) function returned 1 instead of 0.01234567901.
#include < iostream >
#include < cmath >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < (int)exponent; i++)
{
result *= base;
if (i == (int)(exponent - 1) && exponent != (int)exponent)
{
double pow = 1;
for (int j = 0; j < (exponent - (int)exponent); j++)
{
pow *= base;
}
result *= pow;
}
}
if (exponent == 0.5)
result = sqrt(base);
if (exponent < 0)
result = 1 / result;
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
Can you modify your code such that it can handle negative exponents?
#include < iostream >
#include < cmath >
double power(double base, double exponent)
{
double result = 1;
for (int i = 0; i < (int)exponent; i++)
{
result *= base;
if (i == (int)(exponent - 1) && exponent != (int)exponent)
{
double pow = 1;
for (int j = 0; j < (exponent - (int)exponent); j++)
{
pow *= base;
}
result *= pow;
}
}
if (exponent == 0.5)
result = sqrt(base);
if (exponent < 0)
result = 1 / (result * pow(base, abs(exponent)));
return result;
}
int main()
{
double base, exponent;
std::cout << "Enter base: ";
std::cin >> base;
std::cout << "Enter exponent: ";
std::cin >> exponent;
double result = power(base, exponent);
std::cout << base << " to the power of " << exponent << " is " << result << std::endl;
return 0;
}
program_output_0:
Enter base: 25 Enter exponent: 0.5 25 to the power of 0.5 is 5
program_output_1:
Enter base: 5 Enter exponent: -2 5 to the power of -2 is 0.04
program_output_2:
Enter base: 81 Enter exponent: 0.5 81 to the power of 0.5 is 9
program_output_3:
Enter base: -81 Enter exponent: 0.5 -81 to the power of 0.5 is -nan
program_output_4:
Enter base: 100 Enter exponent: -1 100 to the power of -1 is 0.01
This web page was last updated on 29_MARCH_2023. The content displayed on this web page is licensed as PUBLIC_DOMAIN intellectual property.
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